A stationary wave incident on rigid wall. Then the distance between wall and first antinode is (velocity of wave is 36 m/s and frequency 72Hz)
A. 1/2m
B. 1/4m
C. 1/8m
D. 1m

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1 Answers

Correct Answer - C
`lamda = v/n`
`lamda/4 = (v)/(4n)`
`=(36)/(4xx72)`
`lamda/4 = 1/8 m`

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