The distance between two particles on a string is 10 cm. If the frequency of wave propagating in it is 400 Hz and its speed is 100 m/s then the phase
The distance between two particles on a string is 10 cm. If the frequency of wave propagating in it is 400 Hz and its speed is 100 m/s then the phase difference between the particles will be
A. `0.8pi` radian
B. `0.4 pi` radian
C. `0.2 pi` radian
D. `pi` radian
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Correct Answer - A
`d = (2pi x)/(lamda) = (2pi xx 0.1)/((v)/(n)) = (2pi xx 0.1 xx 400)/(100)`
`= 0.8 pi` rad
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