Energy density of wire is `0.25 J//m^(3)`, when its extenstion is 0.2 cm. Find energy of wire, when elongation is 1 cm

Question

Energy density of wire is `0.25 J//m^(3)`, when its extenstion is 0.2 cm. Find energy of wire, when elongation is 1 cm

Energy density of wire is `0.25 J//m^(3)`, when its extenstion is 0.2 cm. Find energy of wire, when elongation is 1 cm
A. `(25)/(4)J//m^(3)`
B. `(1)/(1000)J//m^(3)`
C. `(5)/(4)J//m^(3)`
D. `(25)/(2)J//m^(3)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`(u_(2))/(u_(1))=(l_(2)^(2))/(l_(1)^(2))=((1)/(0.2))^(2) =((10)/(2))^(2)=25`
`u_(2)=0.25 xx 25 =(25)/(4)`

4 views Answered 2023-02-05 15:29