A metal rod of length 2.5m and area of cross-section `2.5xx10^(-4)m^(2)` is elongated by `2.5xx10^(-3)`m by a force of 600N. Then energy stored in the

Question

A metal rod of length 2.5m and area of cross-section `2.5xx10^(-4)m^(2)` is elongated by `2.5xx10^(-3)`m by a force of 600N. Then energy stored in the

A metal rod of length 2.5m and area of cross-section `2.5xx10^(-4)m^(2)` is elongated by `2.5xx10^(-3)`m by a force of 600N. Then energy stored in the rod is,
A. 75 J
B. 0.75 J
C. 25 J
D. 50 J

Monjur Alahi

9 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`W=(1)/(2)Fl`
`=(1)/(2) xx 600 xx 2.5xx10^(-3)=0.75J`.

9 views Answered 2023-02-05 15:29