A long wire hangs vertically with its upper end clamped, when a torque of 4.5 Nm is applied to free end through an angle of `10^(@)`. Then work done by the twisted wire is,
A. `pi//4J`
B. `22.5 J`
C. `pi//2J`
D. `pi//8J`

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1 Answers

Correct Answer - D
`omega =(1)/(2) tau theta =(1)/(2) xx (4.5xx10pi)/(180)=(pi)/(8)`

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