The pressure required to reduce the given volume of water by `1%` is, (Bulk modulus of water `=2xx10^(9)N//m^(2)`)

Question

The pressure required to reduce the given volume of water by `1%` is, (Bulk modulus of water `=2xx10^(9)N//m^(2)`)

The pressure required to reduce the given volume of water by `1%` is,
(Bulk modulus of water `=2xx10^(9)N//m^(2)`)
A. `2xx10^(7)N//m^(2)`
B. `2xx10^(8)N//m^(2)`
C. `2xx10^(10)N//m^(2)`
D. `2xx10^(10)N//m^(2)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`k=(V*dp)/(dV) therefore dp=(k*dV)/(V) = (2xx10^(9)xx1)/(100) = 2xx10^(7)N//m^(2)`.

4 views Answered 2023-02-05 15:29