A wire can be broken by applying a load of 20kg wt. Then the force required to break the wire of twice the diameter and same length, same material, is
A. 5 kg wt
B. 160 kg wt
C. 80 kg wt
D. 20 kg wt

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1 Answers

Correct Answer - C
Breaking force = Stress `xx` Area
`theefore " Stress"=("Breaking force")/("Area")=(20)/(pi D^(2)//4)`
`i.e. (20)/(pi D^(2)//4)=(Fxx4)/(pi (2D)^(2))=80` kg wt

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