A metal wire can be broken by applying a load of 45 kg wt. Then the force required to break the wire of twice the diameter and the same material is
A. 22.5 kg wt
B. 45 kg wt
C. 90 kg wt
D. 180 kg wt

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1 Answers

Correct Answer - D
`(F_(2))/(F_(L))=(r_(2)^(2))/(r_(L)^(2))`
`F_(2)= 4xx45=180 kg wt`.

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