A train leaves Pune at 7 :30 am and reaches Mumbai at 11 : 30 am. Another train leaves Mumbai at 9 : 30 am and reaches Pune at 1 : 00 pm. Assuming tha

Question

A train leaves Pune at 7 :30 am and reaches Mumbai at 11 : 30 am. Another train leaves Mumbai at 9 : 30 am and reaches Pune at 1 : 00 pm. Assuming tha

A train leaves Pune at 7 :30 am and reaches Mumbai at 11 : 30 am. Another train leaves Mumbai at 9 : 30 am and reaches Pune at 1 : 00 pm. Assuming that the two trains at constant speeds, at what time do the two trains cross each other-
A. `10 : 20am`
B. `11:30am`
C. `10:26am`
D. Data not sufficinet

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - B
First train from Pune to Mumbai takes 4hrs.
Second train from Mumbai to Pune takes 3.5hrs.
Speed of train from Pune to Mumbai is `V_(1)=(d)/(4)`
Speed of train from Mumbai to Pune is `V_(2)=(d)/(3.5)`
Distance traveled by first train till 9:30 is `x=(d)/(4)xx2=(d)/(2)`
Say now both trains meet after time from 9:30
`(x)/(d//4)=((d)/(2)-xx)/((d)/(3.5))implies(4x)/(d)=(3.5)/(2)-(3.5x)/(d)implies(7.5x)/(d)=(3.5)/(2)implies15xx=3.5dimplies30xx=7d`
time taken by first train 9:30 is `(4x)/(d)=4((7)/(30))`
`=(14)/(15)`
56min
Then both train meet at 9:30+56min =10:26am