A simple pendulum oscillates with an amplitude of `2xx10^(-2)m`. If the force acting on it at extreme position is 4 N. Then the time that another simp
A simple pendulum oscillates with an amplitude of `2xx10^(-2)m`. If the force acting on it at extreme position is 4 N. Then the time that another simple pendulum of length 81 cm takes to execute the same number of oscillations is
A. 4N
B. 3N
C. 2N
D. 1N
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Correct Answer - C
`(F_(m))/(F_(e))=(kx_(m))/(kx_(e))`
`=((A)/(2))/(A)=(1)/(2)`
`F_(m)=(F_(e))/(2)=(4)/(2)=2N`
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