The displacement x (in metre ) of a particle in, simple harmonic motion is related to time t ( in second ) as ` x= 0.01 cos (pi t + pi /4)` the freque

Question

The displacement x (in metre ) of a particle in, simple harmonic motion is related to time t ( in second ) as ` x= 0.01 cos (pi t + pi /4)` the freque

The displacement x (in metre ) of a particle in, simple harmonic motion is related to time t ( in second ) as
` x= 0.01 cos (pi t + pi /4)`
the frequency of the motion will be
A. 0.5 Hz
B. 1 Hz
C. `pi//2 Hz`
D. `pi Hz`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`omega=pi`
`therefore 2pin=pi therefore n=(1)/(2)=0.5`

5 views Answered 2023-02-05 15:29