The displacement x(in metres) of a particle performing simple harmonic motion is related to time t(in seconds) as `x=0.05cos(4pit+(pi)/4)` .the freque

Question

The displacement x(in metres) of a particle performing simple harmonic motion is related to time t(in seconds) as `x=0.05cos(4pit+(pi)/4)` .the freque

The displacement x(in metres) of a particle performing simple harmonic motion is related to time t(in seconds) as `x=0.05cos(4pit+(pi)/4)` .the frequency of the motion will be
A. 0.5 Hz
B. 1.0 Hz
C. 1.5 Hz
D. 2.0 Hz

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
Compare the given equation with the standard from
`y=a cos [(2pi t)/T-(2pi x)/lambda]`
Coefficient of `t=(2pi)/T=2 pi n=4 pi, n =2` Hz

5 views Answered 2023-02-05 15:29