If the maximum acceleration of a particle performing S.H.M. is numerically equal to twice the maximum velocity then the period will be

Question

If the maximum acceleration of a particle performing S.H.M. is numerically equal to twice the maximum velocity then the period will be

If the maximum acceleration of a particle performing S.H.M. is numerically equal to twice the maximum velocity then the period will be
A. 1.57 s
B. 3.142 s
C. 6.28 s
D. 2 s

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`a_(m)=2v_(m)`
`Aomega^(2)=2Aomega`
`omega=2`
`T=(2pi)/(omega)=(2pi)/(2)=pi=3.142 s`

5 views Answered 2023-02-05 15:29