The maximum speed of a particle executing S.H.M. is 1 m/s and its maximum acceleration is`1.57 m// sec^(2)` . The time period of the particle will be

Question

The maximum speed of a particle executing S.H.M. is 1 m/s and its maximum acceleration is`1.57 m// sec^(2)` . The time period of the particle will be

The maximum speed of a particle executing S.H.M. is 1 m/s and its maximum acceleration is`1.57 m// sec^(2)` . The time period of the particle will be
A. 0.25 `s^(-1)`
B. 2 `s^(-1)`
C. 1.57 `s^(-1)`
D. 2.57 `s^(-1)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

Two particles are executing SHM in a straight line. Amplitude A and the time period T of both the particles are equal. At time t=0, one particle is at

2 Answers 6 Views

The displacement of a particle executing SHM is given by `Y=5 " sin "(4t+(pi)/(3))` If T is the time period and the mass of the particle is 2g, the ki

2 Answers 5 Views

निम्नलिखित समीकरण को हल कीजिए - `sec^(-1)((x)/(a))-sec^(-1)((x)/(b))=sec^(-1)(b)-sec^(-1)(a).`

2 Answers 4 Views

A body of mass 5 gm is executing S.H.M. about a point with amplitude 10 cm . Its maximum velocity is 100 cm / sec . Its velocity will be 50 cm / sec a

2 Answers 5 Views

The time period of a particle executing S.H.M. is 1 s. If the particle starts motion from the mean position, then the time during which it will be at

2 Answers 4 Views

The velocity and acceleration of a particle executing S.H.M. have a steady phase relationship. The acceleration leads velocity in phase by

2 Answers 6 Views

The maximum velocity of a particle executing S.H.M. is u. If the amplitude is doubled and the time period of oscillation decreases to (1/3) of its ori

2 Answers 4 Views

The acceleration of a particle executing SHM at a distance of 3 cm from equilibrium position is `5 cm//s^(2)`. Its acceleration at a distance of 2 cm

2 Answers 4 Views

A particle is executing SHM with an amplitude of 2 m. The difference in the magnitudes of its maximum acceleration and maximum velocity is 4. The time

2 Answers 4 Views

The maximum velocity and maximum acceleration of a particle executing SHM are 20 cm `s^(-1) and 100 cm s^(-2)`. The displacement of the particle from

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`v_(0) = r" "omega = 1 and a_(0) = omega^(2)r = 1.57 ms^(-2)`
`omega = omega^(2)r//r omega = 1.57//1 or 2 pi v = 1.57`
`v = (1.57)/(2 xx 3.14)=(1)/(4)=0.25 s^(-1)`

4 views Answered 2023-02-05 15:29