The time period of S.H.M. is 16 seconds and it starts motion from the equililbrium position, after two seconds the velocity is `pi m//s`. Then the dis

Question

The time period of S.H.M. is 16 seconds and it starts motion from the equililbrium position, after two seconds the velocity is `pi m//s`. Then the dis

The time period of S.H.M. is 16 seconds and it starts motion from the equililbrium position, after two seconds the velocity is `pi m//s`. Then the displacement amplitude is
A. `sqrt(2) m`
B. `2 sqrt(2) m`
C. `4 sqrt(2) m`
D. `8 sqrt(2) m`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`T=(2pi)/(omega) therefore omega=(2pi)/(16)=(pi)/(8)`
`v=Aomegacosomegat`
`therefore pi=A(pi)/(8)cos((pi)/(4))`
`1=(A)/(8)xx(1)/(sqrt(2))`
`therefore A=8sqrt(2)`

4 views Answered 2023-02-05 15:29