A dancer spins about himself with an angular speed `omega`, with his arms extended. When he draws his hands in, his moment of inertia reduces by 40% .

Question

A dancer spins about himself with an angular speed `omega`, with his arms extended. When he draws his hands in, his moment of inertia reduces by 40% .

A dancer spins about himself with an angular speed `omega`, with his arms extended. When he draws his hands in, his moment of inertia reduces by 40% . Then his angular velocity would be
A. `3omega//4`
B. `4omega//5`
C. `5omega//4`
D. `5omega//3`

Monjur Alahi

7 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`w_(2)=(I omega xx 100)/(60I)=(5omega)/(3)`.

7 views Answered 2023-02-05 15:29