The moment of inertia of a ring about one of its diameter is `2 kg m^(2)` . What will be its moment of inertia about a tangent parallel to the diamete

Question

The moment of inertia of a ring about one of its diameter is `2 kg m^(2)` . What will be its moment of inertia about a tangent parallel to the diamete

The moment of inertia of a ring about one of its diameter is `2 kg m^(2)` . What will be its moment of inertia about a tangent parallel to the diameter?
A. `2 kg m^(2)`
B. `6 kg m^(2)`
C. `4 kh m^(2)`
D. `5 kg m^(2)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`I_(d)=(MR^(2))/(2)=2 " " therefore I_(t)=(3)/(2) MR^(2)`

5 views Answered 2023-02-05 15:29