Two bodies with moment of inertia `l_(1)` and `l_(2)` `(l_(1) gt l_(2))` have equal angular momentum. If `E_(1)` and `E_(2)` are the rotational kineti

Question

Two bodies with moment of inertia `l_(1)` and `l_(2)` `(l_(1) gt l_(2))` have equal angular momentum. If `E_(1)` and `E_(2)` are the rotational kineti

Two bodies with moment of inertia `l_(1)` and `l_(2)` `(l_(1) gt l_(2))` have equal angular momentum. If `E_(1)` and `E_(2)` are the rotational kinetic energies, then
A. `E_(1)=E_(2)`
B. `E_(1)lt E_(2)`
C. `E_(1)gt E_(2)`
D. `E_(1) gr E_(2)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`K.E._(1)=(1)/(2)(L^(2))/(I_(1))`
`therefore K.E._(1) prop (1)/(I_(1))`
`K.E._(2)=(1)/(2)(L^(2))/(I_(2)) therefore K.E._(2) prop (1)/(I_(2))`
`(K.E._(2))/(K.E._(1))=(I_(1))/(I_(2))`
`therefore K.E._(1) lt K.E._(2)`

4 views Answered 2023-02-05 15:29