A particle is dropped from height H. At a point its kinetic energy is x times of its potential energy. Find the speed of the particle at that point -

A particle is dropped from height H. At a point its kinetic energy is x times of its potential energy. Find the speed of the particle at that point -
A. `[2gxH]^(1//2)`
B. `[(2g(x+1)H)/(x)]^(1//2)`
C. `[(2gH)/((x+1))]^(1//2)`
D. `[(2gxH)/((x+1))]^(1//2)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - 4
`K.E.=x(P.E.)`
`Or K.E.=((x)/(x+1))T.E.=((x)/(X+1))mgH`
`v=sqrt(2gH((x)/(x+1)))`

4 views Answered 2023-02-05 15:29

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