A ball of mass 1 kg carrying a charge `10^(-8)C` moves from a point A at potential 600 V to a point B at zero potential. The change in its kinetic energy is
A. `-6xx10^(-6)"erg"`
B. `-6xx10^(-6)J`
C. `6xx10^(-6)J`
D. `6xx10^(-6)"erg"`

4 views

1 Answers

Correct Answer - C
As work is done by the fiel, KE of the body increased
`therefore" "DeltaKE=W=q(V_(A)-V_(B))`
`=10^(-8)(600-0)=6xx10^(-6)J`

4 views

Related Questions