One molee of methanol when burnt in `O_(2)`, gives out 723 kJ `mol^(-1)` of heat. If one mole of `O_(2)` is used, what will be the amount of heat evov

Question

One molee of methanol when burnt in `O_(2)`, gives out 723 kJ `mol^(-1)` of heat. If one mole of `O_(2)` is used, what will be the amount of heat evov

One molee of methanol when burnt in `O_(2)`, gives out 723 kJ `mol^(-1)` of heat. If one mole of `O_(2)` is used, what will be the amount of heat evovled?
A. 723 kJ
B. 924 kJ
C. 482 kJ
D. 241 kJ

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`CH_(3)OH(l)+(3)/(2)O_(2)(g) to CO_(2)(g)+2H_(2)O(l),DeltaH=-723kJ`
By burning with `(3)/(2)O_(2)(g)` heat evolved `=-723kJ`
`therefore`By burning with 1 mole `O_(2)(g)=(-723xx2)/(3)=482kJ`

4 views Answered 2023-02-05 15:29