The amount (in mol) of bromoform `(CHBr_(3))` produced when 1.0 mol of acetone reacts completely with 1.0 mol of bromie in the presence of aqueous NaOH is
A. `1/3`
B. `2/3`
C. `1`
D. `2`

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1 Answers

Correct Answer - A
`underset( 1 "mole")(CH_(3)-overset(O) overset(||)C-CH_(3))+3Br^(2)+underset(1 "mole")(4NaOH)toCH_(3)-overset(O)overset(||)C-overset(-)(O)Na^(+)+3NaBr+3H_(2)O+underset(1//3 " mol" )(CHBr_(3))`
Moles of bromoform produced `=1//3` mole

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