Calculate the difference between `DeltaE and DeltaH` for the following reaction at `27^(@)C` (in kcal) `C("graphite")+2H_(2)(g)toCH_(4)(g)`

Question

Calculate the difference between `DeltaE and DeltaH` for the following reaction at `27^(@)C` (in kcal) `C("graphite")+2H_(2)(g)toCH_(4)(g)`

Calculate the difference between `DeltaE and DeltaH` for the following reaction at `27^(@)C` (in kcal)
`C("graphite")+2H_(2)(g)toCH_(4)(g)`
A. `-0.6`
B. `-1.2`
C. `+0.6`
D. `+1.2`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`C("graphite")+2H_(2)(g) to CH_(4)(g)`
`DeltaH=DeltaE+Deltan_(g)RT`
`DeltaE-DeltaH=-Deltan_(g)RT`
`DeltaE-DeltaH=-(-1)xx2xx300`
`=600cal=0.6kcal`

4 views Answered 2023-02-05 15:29