Mole fraction of solute in benzene is `0.2` then what is the value of molality of solute?
A. `3.2`
B. 2
C. 4
D. `3.6`

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1 Answers

Correct Answer - A
Let the solution be x molal, then x moles of solute are present in `1000g" of benzene"=(1000)/(78)=12.82` benzene
`:."Mole fractionof solute"=(x)/(x+12.82)`
`rArr0.=(x)/(x+12.82)`
`x=(2.564)/(0.8)=3.2`

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