The magnetic moment of a current (i) carrying circular coil of radius (r) and number of turns (n) varies as
A. `1//r^2`
B. `1//r `
C. `r `
D. `r^(2) `

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1 Answers

Correct Answer - D
From the formula , the magnetic moment of a current carrying circular coil is given by
`M=niA-nipir^2`
where , r is the radius of circular coil.
Therefore , magnetic moment is proportional to ` r^(2)`.

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