Electrons move at right angles to a magnetic field of `1.5xx10^(-2)` Tesla with a speed of `6xx10^(7)m//s`. If the specific charge of the electron is
Electrons move at right angles to a magnetic field of `1.5xx10^(-2)` Tesla with a speed of `6xx10^(7)m//s`. If the specific charge of the electron is `1.7xx10^(11)C//kg`. The radius of the circular path will be
A. 2.9 cm
B. 3.9 cm
C. 2.35 cm
D. 2cm
4 views
1 Answers
Correct Answer - C
Radius of circular path is
`rarr=(mV)/(B)=(V)/((C)/(m))B=(6xx10^(7))/(1.7xx10^(11)xx1.5xx10^(-2))`
`=2.35xx10^(-2)m=2.35 cm`
4 views
Answered