The lengths of two organ pipes open at both ends are `L and L + d`. If they are sounde together, then the beat frequency will be

Question

The lengths of two organ pipes open at both ends are `L and L + d`. If they are sounde together, then the beat frequency will be

The lengths of two organ pipes open at both ends are
`L and L + d`. If they are sounde together, then the
beat frequency will be
A. `(2Vd)/(L(L+x))`
B. `(2Vd)/(L(L+d))`
C. `(2L(L+d))/(Vd)`
D. `(Vd)/(2L(L+d))`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - d
`n_(1)=V/(2L)and n_(2) = V/(2(L+d))`
`therefore n_(1)-n_(2)=V/2[1/L-1/(L+d)]=(Vd)/(2L(L+d))`

4 views Answered 2023-02-05 15:29