Two sitar strings A and B are slightly out of tune and produce beats of frequency 5 Hz. When the tension in the string B is slightly increased, the be

Question

Two sitar strings A and B are slightly out of tune and produce beats of frequency 5 Hz. When the tension in the string B is slightly increased, the be

Two sitar strings A and B are slightly out of tune and produce beats of frequency 5 Hz. When the tension in the string B is slightly increased, the beat frequency is found to reduce to 3 Hz. If the frequency of string A is 427 Hz, the original frequency of string B is
A. 460 Hz
B. 455 Hz
C. 445 Hz
D. 440 Hz

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`n_(A)=` known frequency `=450` Hz, `n_(B)=?, x=5` Hz which is decreasing after tension is increased (i.e. `x darr)
Hence, `n_(A)darr-n_(B)=x darr` ...(i) corect
`n_(B)-n_(A)=x darr` ...(ii) wrong
`implies n_(B)=n_(A)-x=450-5=445` Hz

5 views Answered 2023-02-05 15:29