Two tuning forks A and B give 6 beats/s. The frequency of B is 432 Hz. When B is filed 4 beats/s are produced. The natural frequency of fork A is
A. 438 Hz
B. 426 Hz
C. 483 Hz
D. 462 Hz

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1 Answers

Correct Answer - B
`n_(A) = n_(B) +- 6`
`= 432 +- 6 = 438 or 426 Hz`
When known fork is filled and sounded with a produces 4 b/s.
`n_(A) = n_(B) +- 4 = 432 +-4 = 436 or 426`
When fork of known frequency is filled its frequency decreases by difference of beat frequency (2Hz).
`:. n_(A) = 426 Hz`

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