The rate constant for a first order reaction is `60 s^(-1).` How much time will it take to reduce the initial concentration of the reactant to its `1/

Question

The rate constant for a first order reaction is `60 s^(-1).` How much time will it take to reduce the initial concentration of the reactant to its `1/

The rate constant for a first order reaction is `60 s^(-1).` How much time will it take to reduce the initial concentration of the reactant to its `1//6^(th)` value ?

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

For `1 ^(st)` order reaction
`t=(2.303)/(k)log ""(a)/((a-x))-(i)`
Given `(a-x) =(a)/(16), k =60s^(-1)`
Placing the values in eq. (i)
`t=(2.303)/(60s^(-1))log ""(axx 16)/(a) =(2.303)/(60s^(-1))log 16`
`=(2.303)/(60s^(-1))log 2^(4)`
`=(2.303)/(60s^(-1))xx4 log 2=(2.303)/(60s^(-1))xx4xx0.3010=4.62xx10^(-2)s`
Time `=4.62 xx10^(-2)s.`