Rate constant for a reaction is `10^(-3) S^(-1)`. How much time is required to reduce the initial concentration of reactant to 25%

Question

Rate constant for a reaction is `10^(-3) S^(-1)`. How much time is required to reduce the initial concentration of reactant to 25%

Rate constant for a reaction is `10^(-3) S^(-1)`. How much time is required to reduce the initial concentration of reactant to 25%
A. 693 s
B. 1386 s
C. 6930 s
D. 2029 s

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

For the first order reaction `AtoB`, the time taken to reduce to `1//4` of initial concentration is 10 min. The time required to reduce to `1//16` of

2 Answers 7 Views

Assertion : The rate of reaction is the rate of change of concentration of a reactant or a product. Reason : Rate of reaction remians constant during

2 Answers 5 Views

A reaction is second order with respect to a reactant. How is the rate of reaction is affected if the concentration of the reactant is i) doubled ii)

2 Answers 4 Views

The rate constant for a first order reaction is `60 s^(-1).` How much time will it take to reduce the initial concentration of the reactant to its `1/

2 Answers 4 Views

For a first order reaction half life is 14 sec. The time required for the initial concentration to reduce 1/8 of the value is

2 Answers 5 Views

The value of rate constant for a first order reaction is 2.303 `xx10^(-2) sec^(-1)` . What will be time required to reduce the concentration to ` (1)/

2 Answers 5 Views

In a zero-order reaction, if the initial concentration of the reactant is doubled, the time required for half the reactant to be consumed

2 Answers 6 Views

The rate of the first reaction `A to ` products is `0.01 M//s ` , when reactant conentration concentration is 0.2 M . The rate constant for the ractio

2 Answers 7 Views

Initial concentration of reactant of Zero order reaction is 0.04 M, rate constant of the reaction is `1.2xx10^(-3) mol dm^(-3) sec^(-1)` . Hence the h

2 Answers 4 Views

The rate constant for a first order reaction is `7.0xx10^(-4) s^(-1) `. If initial concentration of reactant is 0.080 M, what is the half life of reac

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - B
`t=(2.303)/(K)"log"(a)/(a-x)`
where," "k=rate constant=`10^(-3)s^(-1)`
a=I"initial amount "=100
a-x= amount left after time, t =25
t=time required to reduce the initial concentration of reactant to 25% reaction
`therefore " " t=(2.303)/(10^(-3))"log"(100)/(25)=(2.303)/(10^(-3))`"log" 4
=` (2.303xx0.6020)/(10^(-3))=1386s`