A first order reaction has a rate constant `1.15xx10^(-3)s^(-1)`. How long will `5g` of this reactant take to reduce to `3g`` ?

Question

A first order reaction has a rate constant `1.15xx10^(-3)s^(-1)`. How long will `5g` of this reactant take to reduce to `3g`` ?

A first order reaction has a rate constant `1.15xx10^(-3)s^(-1)`. How long will `5g` of this reactant take to reduce to `3g`` ?
A. 444s
B. 400s
C. 528s
D. 669s

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`t = (2.303)/(k) "log" ([R_(0)])/([R]) = (2.303)/(1.15 xx 10^(-3)) "log" (5)/(3)`
`=2.00 xx 10^(3) log 1.667 = 2 xx 10^(3) xx 0.2219 = 444s`

5 views Answered 2023-02-05 15:29