The initial concentratin of `N_(2)O_(5)` in the following first order reaction `N_(2)O_(5)(g) to 2NO_(2)(g)+(1)/(2O_(2))(g) was 1.24 xx10^(-2) mol L^(

Question

The initial concentratin of `N_(2)O_(5)` in the following first order reaction `N_(2)O_(5)(g) to 2NO_(2)(g)+(1)/(2O_(2))(g) was 1.24 xx10^(-2) mol L^(

The initial concentratin of `N_(2)O_(5)` in the following first order reaction
`N_(2)O_(5)(g) to 2NO_(2)(g)+(1)/(2O_(2))(g) was 1.24 xx10^(-2) mol L^(-1)` at 318K. The concentration of `N_(2)O_(5)` after 60 minutes was `0.20xx10^(-2) mol L^(-1).` Calculate the rate constant of the reaction at 138 K.

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

For a first order reaction
`log ""([R]_(1))/([R]_(2))=(k(t_(2)-t_(1)))/(2.303)`
`k= (2.303)/((t_(2)- t_(1)))log ""([R_(1)])/([R]_(2))`
`=(2.303)/((60 min -0min ))log ""(1.24xx10^(-2)mol L ^(-1))/(0.20xx10^(-2)mol L^(-1))`
`=(2.303)/(60)log 6.2 min ^(-1)`
`k=0.0304min^(-1).`

4 views Answered 2023-02-05 15:29