Calculate the half life of the reaction `ArarrB`, when the initial concentration of A is `0.01 "mol" L^(-1)` and initial rate is `0.00352 "mol" L^(-1)

Question

Calculate the half life of the reaction `ArarrB`, when the initial concentration of A is `0.01 "mol" L^(-1)` and initial rate is `0.00352 "mol" L^(-1)

Calculate the half life of the reaction `ArarrB`, when the initial concentration of A is `0.01 "mol" L^(-1)` and initial rate is `0.00352 "mol" L^(-1)"min"^(-1)`. The reaction is of the first order
A. 19.69 min
B. 1.969 min
C. 7.75 min
D. 77.5 min

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`(dx)/(dt) = k [X]` (for a first order reaction)
`0.00352 = k xx 0.01 implies k = 0.352`
`t_(1//2) = (0.693)/(k) = (0.693)/(0.352) = 1.969` min

5 views Answered 2023-02-05 15:29