If 1 g of solute (molar mass = `50 g mol^(-1)`) is dissolved in 50 g of solvent and the elevation in boiling point is 1 K. The molar boiling constant

Question

If 1 g of solute (molar mass = `50 g mol^(-1)`) is dissolved in 50 g of solvent and the elevation in boiling point is 1 K. The molar boiling constant

If 1 g of solute (molar mass = `50 g mol^(-1)`) is dissolved in 50 g of solvent and the elevation in boiling point is 1 K. The molar boiling constant of the solvent is
A. 2
B. 3
C. 2.5
D. 5

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

If `30g` of a solute of molecular weight `154` is dissolved in `250 g` of benzene. What will be the elevation in boiling point - (Given : `K_(b(C_(e)H

2 Answers 4 Views

The boiling a point of benzene is 353.23K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.1

2 Answers 4 Views

The boiling point of benzene is 353 .23 K. When 1.80 gram of non- volatile solute was dissolved in 90 gram of benzene , the boiling point is raised to

2 Answers 5 Views

Boiling point of a solvent is `80.2.^(@)C` When 0.419 g of the solute of molar mass 252 .4 g `mol^(-1)` is dissolved in 75 g of the above solvent the

2 Answers 7 Views

The elevation in boiling point of a solution of 9.43 g of `MgCl_2` in 1 kg of water is ( `K_b` = 0.52 K kg `mol^(-1)` , Molar mass of `MgCl_2 = 94.3 g

2 Answers 5 Views

The boiling point of benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11

2 Answers 5 Views

An aqueous solution of `2%` non volatile solute exerts a pressure of 1.004 bar at the normal boiling point of the solvent. What is the molecular mass

2 Answers 6 Views

Calculate the boiling point of solution containing `0.456g` of camphor (molar mass =152 ) dissolved in `31.4g` of acetone (boiling point `=56.30^(@)C`

2 Answers 8 Views

If M is molecular of solvent, `K_(b)` is molal elevation constant, `T_(b)` is its boiling point, `P^(@)` is its vapour pressure at temperature T and `

2 Answers 5 Views

The mass of a non-volatile solute of molar mass `40g" "mol^(-1)` that should be dissolved in 114 g of octane to lower its vapour pressure by 20% is

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`DeltaT_b=K_bxxm`
or `K_b=(DeltaT_b)/m=1/(1/50xx1000/50)=5/2=2.5`

5 views Answered 2023-02-05 15:29