Boiling point of a solvent is `80.2.^(@)C` When 0.419 g of the solute of molar mass 252 .4 g `mol^(-1)` is dissolved in 75 g of the above solvent the

Question

Boiling point of a solvent is `80.2.^(@)C` When 0.419 g of the solute of molar mass 252 .4 g `mol^(-1)` is dissolved in 75 g of the above solvent the

Boiling point of a solvent is `80.2.^(@)C` When 0.419 g of the solute of molar mass 252 .4 g `mol^(-1)` is dissolved in 75 g of the above solvent the boiling point of the solution is found to be 80. 256 `.^(@)C`
Final the molal elevation constant

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

`K_(b)= 2.53 K kg mol^(-1)`

7 views Answered 2023-02-05 15:29