The self inductance of an inductance coil having 100 turns is 20 mH. Calculate the magnetic flux through the cross section of the coil corresponding t
The self inductance of an inductance coil having 100 turns is 20 mH. Calculate the magnetic flux through the cross section of the coil corresponding to a current of 4 milliampere. Also, find the total flux
A. `2xx10^(-5)Wb`
B. `4xx10^(-7)Wb`
C. `8xx10^(-7)Wb`
D. `8xx10^(-5)Wb`
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Correct Answer - C
Total megnetic flux,
`Nphi=LI=20xx10^(-3)xx4xx10^(-3)=8xx10^(-5)Wb`
Megnetic flux through the corss-section of the coil,
`phi=(8xx10^(-5))/(N)(10xx^(-5))/(100)=8xx10^(-1)Wb`
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