If the self inductance of 500 turns coil is 125 mH, then the self inductance of the similar coil of 800 turns is
If the self inductance of 500 turns coil is 125 mH, then the self inductance of the similar coil of 800 turns is
A. `48.8 mH`
B. 200 mH
C. 290 mH
D. 320 mH
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Correct Answer - D
As `(L_(1))/(L_(2))=(N_(1)^(2))/(N_(2)^(2))`
Here seolrf inductance of 500 turns coil=125mH
`:.` L for coil of 800 turns `=(125)/((500)^(2))xx(800)^(2)=320 mH`
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