If the self inductance of 500 turns coil is 125 mH, then the self inductance of the similar coil of 800 turns is
A. `48.8 mH`
B. 200 mH
C. 290 mH
D. 320 mH

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1 Answers

Correct Answer - D
As `(L_(1))/(L_(2))=(N_(1)^(2))/(N_(2)^(2))`
Here seolrf inductance of 500 turns coil=125mH
`:.` L for coil of 800 turns `=(125)/((500)^(2))xx(800)^(2)=320 mH`

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