A force of 2.25 N acts on a charge of `15xx10^(-4)C`. The intensity of electric field at that point is

Question

A force of 2.25 N acts on a charge of `15xx10^(-4)C`. The intensity of electric field at that point is

A force of 2.25 N acts on a charge of `15xx10^(-4)C`. The intensity of electric field at that point is
A. `150NC^(-1)`
B. `15NC^(-1)`
C. `1500NC^(-1)`
D. `1.5NC^(-1)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
Electric field, `E=F/q=(2.25N)/(15xx10^(-4))=1500NC^(-1)`

4 views Answered 2023-02-05 15:29