An electron experiences a force equal to its weight, when placed in an electric field. The intensity of the field will be

Question

An electron experiences a force equal to its weight, when placed in an electric field. The intensity of the field will be

An electron experiences a force equal to its weight, when placed in an electric field. The intensity of the field will be
A. `1.7xx10^(-11)N//C`
B. `5.0xx10^(-11)N//C`
C. `5.5xx10^(-11)N//C`
D. `56N//C`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
Force acting on electron, F = qE
`rArr" "E=(F)/(q)=(mg)/(e)=(9xx10^(-31)xx9.8)/(16xx10^(-19))`
The intensity of electric field, `E=5.5xx10^(-11)"NC"^(-1)`

4 views Answered 2023-02-05 15:29