An electromagnetic wave going through vacuum is described by `vecE=E_(0)sin(kx-wt) and vecB=B_(0)sin(kx-wt)`. Which of the following equation is true?
An electromagnetic wave going through vacuum is described by `vecE=E_(0)sin(kx-wt) and vecB=B_(0)sin(kx-wt)`. Which of the following equation is true?
A. `E_(0)k=B_(0)omega`
B. `E_(0)omega=B_(0)k`
C. `E_(0)B_(0)=omega k`
D. `E_(0)omegak=B_(0)`
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Correct Answer - A
We know that `E_(0)=CB_(0)`, where C is velocity of light
thus, `E_(0)=(omega)/(K)B_(0) because C=(omega)/(K)" or "E_(0)K=B_(0)omega`
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