An e.m. wave travels in vacuum along z direction: `vecE=(E_1hati+E_2hatj)cos (kz-omega)`. Choose the correct option from the following :

Question

An e.m. wave travels in vacuum along z direction: `vecE=(E_1hati+E_2hatj)cos (kz-omega)`. Choose the correct option from the following :

An e.m. wave travels in vacuum along z direction:
`vecE=(E_1hati+E_2hatj)cos (kz-omega)`. Choose the correct option from the following :
A. The associated magnetic field is given as
`B=1/C (E_(1)hati -E_(2)hatj) " cos " (kz - omegat)`
B. The associated magnetic field is given as
`B=1/c (E_(1) hati -E_(2) hatj) " cos "(kz- omegat)`
C. The given electromagnetic field is circulary polarised
D. The given electromagnetic wave is plane polarised

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - D
Here, in electromagnetic wave the electric field vector is given as ,
`E=(E_(1)hati +E_(2) hatj " cos " (kz -omegat)`
in electromagnetic wave ,the associated magnetic field vector.
`B =E/C = (E_(1)hati +E_(2)hatj)/(C)" cos "(kz-omegat)`
Also E and B are perpendicular to each other and the propagation of electromagnetic wave is perpendicular to E as well as B so the given electromagnetic wave is plane polarised.