For decolourisation of 1.5 moles of `KMnO_(4)` the moles of `H_(2)O_(2)` requires
For decolourisation of 1.5 moles of `KMnO_(4)` the moles of `H_(2)O_(2)` requires
A. `(3)/(2)`
B. `(9)/(4)`
C. `(15)/(4)`
D. `(21)/(4)`
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Correct Answer - C
Equivalents of `KMnO_(4)`=Equivalents of `H_(2)O_(2)1.5xx5=x xx2`
`x=(1.5xx5)/(2)=(15)/(4)`
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