In the preparation of `HNO_(3)`, we get NO gas by catalytic oxidation of ammonia . The moles of No produced by the oxidation of two moles of `NH_(3)`
In the preparation of `HNO_(3)`, we get NO gas by catalytic oxidation of ammonia . The moles of No produced by the oxidation of two moles of `NH_(3)` will be ……… .
A. 2
B. 3
C. 4
D. 6
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Correct Answer - A
`4NH_(3"(g)")+underset("(from air)")(5O_(2"(g)"))overset("Pt/Rh gauge catalyst")underset("500 K, 9 bar")rarr4NO_("(g)")+6H_(2)O_("(g)")`
Thus, 2 moles of NO will be produced by the oxidation of 2 moles of `NH_(3)`.
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