For the second order reaction, `A+Brarr"products"` when a moles of A react with b moles of B, the rate equation is given by `k_(2)t=(1)/(a-b)In(b(a-x)

Question

For the second order reaction, `A+Brarr"products"` when a moles of A react with b moles of B, the rate equation is given by `k_(2)t=(1)/(a-b)In(b(a-x)

For the second order reaction,
`A+Brarr"products"`
when a moles of A react with b moles of B, the rate equation is given by
`k_(2)t=(1)/(a-b)In(b(a-x))/(a(b-x))`
when `agtgtb,` the rate expression becomes that of
A. first order
B. zero order
C. unchanged, second order
D. third order

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`A+Brarr"products"`
when `agtgtb` i.e. reactant A is present in large excess, the rate of reactant will not depend upon its concentration.
Hence, it will be of first order.

4 views Answered 2023-02-05 15:29