The standard reduction potential for ` Mg^(2+)//Mg` is -2.37 V and for `Cu^(2+)//Cu` is 0.337 . The `E_("cell")^(@)` for the following reaction is
` Mg+Cu^(2+) to Mg^(2+)+Cu`
A. `+2.03`V
B. `-2.03 V`
C. `-2.7 V`
D. `+2.7V`

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Correct Answer - D
`E_("cell")^(@)=E_("cathode")^(@)-E_("anode")^(@)`
`=E_((Cu^(@+)//Cu))^(@)-E_((Mg^(2+)//Mg))^(@)=0.337-(-2.37)V=2.7V`

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