The standard electrode potential for Deniell cell is `1.1V`. Calculate the standard Gibbs energy for the reaction.
`Zn(s) +Cu^(2+)(aq) hArr Zn^(2+)(aq)+Cu(s)`

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1 Answers

We know, `DeltaG^(0)=-nFE^(@)`…(i)
n=2 for the given reaction F=96500C, `E^(@)=+1.1V`
`therefore` from (i) `DeltaG^(0)=-2xx96500xx1.1=-212300J`

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