The electron in the hydrogen atom is moving with a speed of `2.5 xx 10^(6)` m/s in an orbit of radius 0.5 `Å`. Magnetic moment of the revolving electr

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The electron in the hydrogen atom is moving with a speed of `2.5 xx 10^(6)` m/s in an orbit of radius 0.5 `Å`. Magnetic moment of the revolving electr

The electron in the hydrogen atom is moving with a speed of `2.5 xx 10^(6)` m/s in an orbit of radius 0.5 `Å`. Magnetic moment of the revolving electron is

Monjur Alahi

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2025-01-04 04:42

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Given : `v=2.3xx10^(6)m//s, r=0.53 "Å"=0.53 xx10^(-10)m`
Time period of revolution is given by,
`T=(2pi r)/(v)`
Substituting the value, we get
`T=(2xx3.14 xx0.53xx10^(-10))/(2.3xx10^(6))`
`T=(1.06xx3.142xx10^(-16))/(2.3)`
`=(3.33052xx10^(-16))/(2.3)`
`T=1.448xx10^(-16)s`

4 views Answered 2023-02-05 15:29