A bag contains 6 red balls and some blue balls. If the probability of drawing a blue ball the bag is twice that of a red ball,
A bag contains 6 red balls and some blue balls. If the probability of drawing a blue ball the bag is twice that of a red ball, find the number of blue balls in the bag.
5 views
1 Answers
No of red balls = 6
Let no. of blue balls = x
Total no. of possible outcomes = 6 + x(total no. of balls)
P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes)
P(blue ball) = 2 P(red ball)
⇒x /(x+6) = 2(6)/(x+6)
⇒ x = 2(6)
x = 12
∴ No of blue balls = 12
5 views
Answered