A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is:
A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is:
(i) Red
(ii) Black
3 Answers
Total no. of possible outcomes = 8 {3 red, 5 black}
(i) Let E ⟶ event of drawing red ball.
No. favourable outcomes = 1 {1 ace card}
P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes) = 3/8
(ii) Let E ⟶ event of drawing black ball.
No. favourable outcomes = 5 {5 black balls}
P(E) = 5/8
Given: A bag contains 3 red, and 5 black balls. A ball is drawn at random
Required to find: Probability of getting a
(i) red ball
(ii) white ball
Total number of balls 3 + 5 = 8
(i) Total number red balls are 3
We know that, Probability = Number of favourable outcomes/ Total number of outcomes
Thus, the probability of drawing a red ball = 3/8
(ii) Total number of black ball are 5
We know that, Probability = Number of favourable outcomes/ Total number of outcomes
Thus, the probability of drawing a black ball = 5/8
(i) Red
Total numbers of red balls = 3
Number of black balls = 5
Total number of balls = 3 + 5 = 8
Probability of getting a red ball is = Total number of red balls/Total number of balls
= 3/8
∴ Probability of getting a red ball is 3/8
(ii) Black
Total numbers of red balls = 3
Number of black balls = 5
Total number of balls = 3 + 5 = 8
Probability of getting a black ball is = Total number of black balls/Total number of balls
= 5/8
∴ Probability of getting a black ball is 5/8